C++ programming to find the weather a year is a leap or not that year entered by the user?
This c++ language programming is free all type of errors like the compiler and runtime errors and this programming is tested to compile and then run the program code.
Here is only programming code with the output. This programming output is customized to understand easily.
Program to find whether a year is a leap or not in c++
#include
using namespace std;
class Test {
public:
int year;
void show_laep_year(int year) {
if (year % 100 != 0) {
if (year % 4 == 0) {
cout<<“The year “<< year << ” is a Leap Year”;
}
else {
cout<<“The year “<< year << ” is not a Leap Year”;
}
} else {
if (year % 400 == 0) {
cout<<“The year “<< year << ” is a Leap Year”;
}
else {
cout<<“The year “<< year << ” is not a Leap Year”;
}
}
}
}
int main(){
test1 o = new test1();
cout<<“Please Enter a Year: “;
cin>>o.year;
o.show_laep_year(o.year);
}
}
Please Enter a Year: 2016
The year 2016 is a Leap Year
Please Enter a Year: 2015
The year 2015 is not a Leap Year
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